(n^2-3n)-(n^2-3n)=32

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Solution for (n^2-3n)-(n^2-3n)=32 equation: 


Simplifying
(n2 + -3n) + -1(n2 + -3n) = 32

Reorder the terms:
(-3n + n2) + -1(n2 + -3n) = 32

Remove parenthesis around (-3n + n2)
-3n + n2 + -1(n2 + -3n) = 32

Reorder the terms:
-3n + n2 + -1(-3n + n2) = 32
-3n + n2 + (-3n * -1 + n2 * -1) = 32
-3n + n2 + (3n + -1n2) = 32

Reorder the terms:
-3n + 3n + n2 + -1n2 = 32

Combine like terms: -3n + 3n = 0
0 + n2 + -1n2 = 32
n2 + -1n2 = 32

Combine like terms: n2 + -1n2 = 0
0 = 32

Solving
0 = 32

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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